674. Longest Continuous Increasing Subsequence

674. Longest Continuous Increasing Subsequence

Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).

Example 1:

Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4. 

Example 2:

Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1. 

Note: Length of the array will not exceed 10,000.

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class Solution {
    public int findLengthOfLCIS(int[] nums) {
        if (nums.length == 0) return 0;
        
        int len = 1;
        int start = 0;
        for (int i = 1; i < nums.length; i++) {
            if (nums[i] <= nums[i - 1]) {
                start = i;
            }
            
            len = Math.max(len, i - start + 1);
        }
        
        return len;
    }
}