Given an array of integers and an integer k, you need to find the total number of continuous subarrays whose sum equals to k.
Example 1:
Input:nums = [1,1,1], k = 2 Output: 2
Note:
- The length of the array is in range [1, 20,000].
- The range of numbers in the array is [-1000, 1000] and the range of the integer k is [-1e7, 1e7].
注意一些特殊情况,(会对代码的顺序有一点影响)
sum == k
k == 0
class Solution {
public int subarraySum(int[] nums, int k) {
Map<Integer, Integer> map = new HashMap<>();
int count = 0;
int sum = 0;
map.put(0, 1);
for (int i = 0; i < nums.length; i++) {
sum += nums[i];
if (map.containsKey(sum - k)) {
count += map.get(sum - k);
}
map.put(sum, map.getOrDefault(sum, 0) + 1);
}
return count;
}
}
No comments:
Post a Comment