460. LFU Cache
Hard
Design and implement a data structure for Least Frequently Used (LFU) cache. It should support the following operations:
get and put.get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.put(key, value) - Set or insert the value if the key is not already present. When the cache reaches its capacity, it should invalidate the least frequently used item before inserting a new item. For the purpose of this problem, when there is a tie (i.e., two or more keys that have the same frequency), the least recently used key would be evicted.
Follow up:
Could you do both operations in O(1) time complexity?
Could you do both operations in O(1) time complexity?
Example:
LFUCache cache = new LFUCache( 2 /* capacity */ ); cache.put(1, 1); cache.put(2, 2); cache.get(1); // returns 1 cache.put(3, 3); // evicts key 2 cache.get(2); // returns -1 (not found) cache.get(3); // returns 3. cache.put(4, 4); // evicts key 1. cache.get(1); // returns -1 (not found) cache.get(3); // returns 3 cache.get(4); // returns 4
1个hashmap存key - value
1个存key - frequency
1个存 frequency - keys
用min来存最小的frequency
LinkedHashSet里面是hashset + doubly linked list的实现方式,所以是有序的
class LFUCache {
private Map<Integer, Integer> map;
private Map<Integer, Integer> keyToFrq;
private Map<Integer, LinkedHashSet<Integer>> frqToKeys;
private int cap;
private int min;
public LFUCache(int capacity) {
min = -1;
cap = capacity;
map = new HashMap<>();
keyToFrq = new HashMap<>();
frqToKeys = new HashMap<>();
}
public int get(int key) {
if (!map.containsKey(key)) return-1;
int frq = keyToFrq.get(key);
frqToKeys.get(frq).remove(key);
if (min == frq && frqToKeys.get(frq).isEmpty()) min++;
frq++;
if (!frqToKeys.containsKey(frq)) frqToKeys.put(frq, new LinkedHashSet<Integer>());
frqToKeys.get(frq).add(key);
keyToFrq.put(key, keyToFrq.get(key) + 1);
return map.get(key);
}
public void put(int key, int value) {
if (cap <= 0) return;
if (map.containsKey(key)) {
map.put(key, value);
get(key);
return;
}
if (map.size() >= cap) {
int evit = frqToKeys.get(min).iterator().next();
frqToKeys.get(min).remove(evit);
map.remove(evit);
keyToFrq.remove(evit);
}
map.put(key, value);
min = 1;
keyToFrq.put(key, min);
if (!frqToKeys.containsKey(min)) frqToKeys.put(min, new LinkedHashSet<Integer>());
frqToKeys.get(min).add(key);
}
}
/**
* Your LFUCache object will be instantiated and called as such:
* LFUCache obj = new LFUCache(capacity);
* int param_1 = obj.get(key);
* obj.put(key,value);
*/
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