Given a nested list of integers, implement an iterator to flatten it.
Each element is either an integer, or a list -- whose elements may also be integers or other lists.
Example 1:
Given the list
Given the list
[[1,1],2,[1,1]],
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be:
[1,1,2,1,1].
Example 2:
Given the list
Given the list
[1,[4,[6]]],
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be:
-------------------------------[1,4,6].一种说法认为不应该把给出的list转换并存在本地,应该直接在上面遍历
阅读:Java的Iterator class和ListIterator class
没什么可说的
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
*
* // @return true if this NestedInteger holds a single integer, rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds, if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // @return the nested list that this NestedInteger holds, if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
public class NestedIterator implements Iterator<Integer> {
private int index;
private List<Integer> list;
public NestedIterator(List<NestedInteger> nestedList) {
list = getList(nestedList);
index = 0;
}
private List<Integer> getList(List<NestedInteger> nestedList) {
List<Integer> l = new ArrayList<>();
for (NestedInteger n : nestedList) {
if (n.isInteger()) {
l.add(n.getInteger());
}else {
l.addAll(getList(n.getList()));
}
}
return l;
}
@Override
public Integer next() {
int save = list.get(index);
index++;
return save;
}
@Override
public boolean hasNext() {
return index < list.size();
}
}
/**
* Your NestedIterator object will be instantiated and called as such:
* NestedIterator i = new NestedIterator(nestedList);
* while (i.hasNext()) v[f()] = i.next();
*/
Solution #2, 用stack
ToDo: https://leetcode.com/problems/flatten-nested-list-iterator/discuss/80147/Simple-Java-solution-using-a-stack-with-explanation
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